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license_class: Generalize license_ok function

Add dont_want_licenses as parameter to license_ok function and move it
to oe.license module in order to use in other modules.

(From OE-Core rev: 243fe3a4583a21ad6c0b2a26196ed18d41740f7a)

Signed-off-by: Aníbal Limón <anibal.limon@linux.intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
Aníbal Limón преди 10 години
родител
ревизия
8c7082de0a
променени са 2 файла, в които са добавени 18 реда и са изтрити 17 реда
  1. 4 17
      meta/classes/license.bbclass
  2. 14 0
      meta/lib/oe/license.py

+ 4 - 17
meta/classes/license.bbclass

@@ -341,36 +341,23 @@ def incompatible_license(d, dont_want_licenses, package=None):
     take into consideration 'or' operand.  dont_want_licenses should be passed
     as canonical (SPDX) names.
     """
-    import re
     import oe.license
-    from fnmatch import fnmatchcase as fnmatch
     license = d.getVar("LICENSE_%s" % package, True) if package else None
     if not license:
         license = d.getVar('LICENSE', True)
 
-    def license_ok(license):
-        for dwl in dont_want_licenses:
-            # If you want to exclude license named generically 'X', we
-            # surely want to exclude 'X+' as well.  In consequence, we
-            # will exclude a trailing '+' character from LICENSE in
-            # case INCOMPATIBLE_LICENSE is not a 'X+' license.
-            lic = license
-            if not re.search('\+$', dwl):
-                lic = re.sub('\+', '', license)
-            if fnmatch(lic, dwl):
-                return False
-        return True
-
     # Handles an "or" or two license sets provided by
     # flattened_licenses(), pick one that works if possible.
     def choose_lic_set(a, b):
-        return a if all(license_ok(lic) for lic in a) else b
+        return a if all(oe.license.license_ok(lic, dont_want_licenses) \
+		 for lic in a) else b
 
     try:
         licenses = oe.license.flattened_licenses(license, choose_lic_set)
     except oe.license.LicenseError as exc:
         bb.fatal('%s: %s' % (d.getVar('P', True), exc))
-    return any(not license_ok(canonical_license(d, l)) for l in licenses)
+    return any(not oe.license.license_ok(canonical_license(d, l), \
+		dont_want_licenses) for l in licenses)
 
 def check_license_flags(d):
     """

+ 14 - 0
meta/lib/oe/license.py

@@ -5,6 +5,20 @@ import ast
 import re
 from fnmatch import fnmatchcase as fnmatch
 
+def license_ok(license, dont_want_licenses):
+    """ Return False if License exist in dont_want_licenses else True """
+    for dwl in dont_want_licenses:
+        # If you want to exclude license named generically 'X', we
+        # surely want to exclude 'X+' as well.  In consequence, we
+        # will exclude a trailing '+' character from LICENSE in
+        # case INCOMPATIBLE_LICENSE is not a 'X+' license.
+        lic = license
+        if not re.search('\+$', dwl):
+            lic = re.sub('\+', '', license)
+        if fnmatch(lic, dwl):
+            return False
+    return True
+
 class LicenseError(Exception):
     pass